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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A solid disc of mass M is just held in air horizontally by throwing 40 stones per sec vertically upwards to strike the disc each with a velocity 6 \[m{{s}^{-1}}\]. If the mass of each stone is \[0.05kg\] what is the mass of the disc\[(g=10m{{s}^{-2}}\])                                     [Kerala (Engg.) 2001]

    A)             \[1.2kg\]          

    B)             \[0.5kg\]

    C)             \[20kg\]           

    D)             3kg

    Correct Answer: A

    Solution :

                    Weight of the disc will be balanced by the force applied by the bullet on the disc in vertically upward direction.             \[F=nmv=40\times 0.05\times 6=Mg\]             Þ \[M=\frac{40\times 0.05\times 6}{10}=1.2\,kg\]


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