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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A body of mass 40 gm is moving with a constant velocity of 2 cm/sec on a horizontal frictionless table. The force on the table is                          [NCERT 1978]

    A)                         39200 dyne            

    B)                           160 dyne            

    C)                         80 dyne            

    D)                           Zero dyne

    Correct Answer: A

    Solution :

                                Force on the table = mg =\[40\times 980=\]39200 dyne            


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