JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    An object with a mass 10 kg moves at a constant velocity of 10 m/sec. A constant force then acts for 4 second on the object and gives it a speed of 2 m/sec in opposite direction. The acceleration produced in it, is                [CPMT 1971]

    A)                              \[3\,m/{{\sec }^{2}}\]          

    B)                           \[-3\,m/{{\sec }^{2}}\]          

    C)                         \[0.3\,m/{{\sec }^{2}}\]            

    D)                           \[-0.3\,m/{{\sec }^{2}}\]

    Correct Answer: B

    Solution :

                              \[\vec{a}=\frac{\overrightarrow{{{v}_{2}}}-\overrightarrow{{{v}_{1}}}}{t}=\frac{(-2)-(+10)}{4}=\frac{-12}{4}=-3\ m/{{s}^{2}}\]          


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