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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A particle of mass 0.3 kg is subjected to a force \[F=-kx\] with \[k=15\,N/m.\] What will be its initial acceleration if it is released from a point 20 cm away from the origin [AIEEE 2005]

    A)             5 m/s2

    B)               10 m/s2

    C)             3 m/s2

    D)             15 m/s2

    Correct Answer: B

    Solution :

                    Force on particle at 20 cm away \[F=kx\] F = 15 × 0.2 = 3 N   \[\left[ \text{As }k=15\ N/m \right]\]             \[\therefore \] Acceleration = \[\frac{\text{Force}}{\text{Mass}}=\frac{3}{0.3}=10\,m/{{s}^{2}}\]


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