JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    At a place where the acceleration due to gravity is \[10\,m\,{{\sec }^{-2}}\] a force of 5 kg-wt acts on a body of mass 10 kg initially at rest. The velocity of the body after 4 second is [EAMCET 1981]          

    A)                              \[5\,m\,{{\sec }^{-1}}\]            

    B)                           \[10\,m\,{{\sec }^{-1}}\]            

    C)                       \[20\,m\,{{\sec }^{-1}}\]          

    D)                           \[50\,m\,{{\sec }^{-1}}\]

    Correct Answer: C

    Solution :

                              Acceleration \[=\frac{\text{Force}}{\text{Mass}}=\frac{50\ N}{10\ kg}=5\ m/{{s}^{2}}\]             From \[v=u+at=0+5\times 4=20\ m/s\]          


You need to login to perform this action.
You will be redirected in 3 sec spinner