2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. NLM, Friction, Circular Motion

JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A ball of mass 0.2 kg moves with a velocity of 20 m/sec and it stops in  0.1 sec; then the force on the ball is            [BHU 1995]

    A)                         40 N             

    B)                         20 N            

    C)                         4 N                 

    D)                         2 N

    Correct Answer: A

    Solution :

                                \[F=ma\] \[=\frac{m\Delta v}{\Delta t}=\frac{0.2\times 20}{0.1}=40\ N\]            


You need to login to perform this action.
You will be redirected in 3 sec spinner