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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A vehicle of 100 kg is moving with a velocity of 5 m/sec. To stop it in \[\frac{1}{10}\sec \], the required force in opposite direction is [MP PET 1995]            

    A)                              5000 N            

    B)                         500 N            

    C)                         50 N               

    D)                         1000 N

    Correct Answer: A

    Solution :

                                \[F=m\ \left( \frac{dv}{dt} \right)=\frac{100\times 5}{0.1}=5000\ N\]                   


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