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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A diwali rocket is ejecting 0.05 kg of gases per second at a velocity of 400 m/sec. The accelerating force on the rocket is [NCERT 1979; DPMT 2001; MP PMT 2004]            

    A)                              20 dynes          

    B)                                       20 N            

    C)                         22 dynes            

    D)                           1000 N

    Correct Answer: B

    Solution :

                                \[F=u\left( \frac{dm}{dt} \right)=400\times 0.05=20\ N\]            


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