A) \[2.2\times {{10}^{3}}N\]
B) \[3.2\times {{10}^{3}}N\]
C) \[4.2\times {{10}^{3}}N\]
D) \[5.2\times {{10}^{3}}N\]
Correct Answer: D
Solution :
\[u=250\,m/s\], \[v=0\], \[s=0.12\,metre\] \[F=ma=m\left( \frac{{{u}^{2}}-{{v}^{2}}}{2s} \right)=\frac{20\times {{10}^{-3}}\times {{(250)}^{2}}}{2\times 0.12}\] \[\therefore \] \[F=5.2\times {{10}^{3}}\,N\]
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