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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A body of mass 2 kg is moving with a velocity 8 m/s on a smooth surface. If it is to be brought to rest in 4 seconds, then the force to be applied is                          [Pb. PMT 2000]

    A)             8 N     

    B)             4 N

    C)             2 N     

    D)             1 N

    Correct Answer: B

    Solution :

                    \[F=ma=\frac{m(u-v)}{t}=\frac{2\times (8-0)}{4}=4N\]


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