JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A monkey of mass 20kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope \[(g=10m/{{s}^{2}})\]                             [CBSE PMT 2003]

    A)             \[10\,m/{{s}^{2}}\] 

    B)             \[25\,m/{{s}^{2}}\]

    C)             \[2.5m/{{s}^{2}}\]

    D)               \[5m/{{s}^{2}}\]

    Correct Answer: C

    Solution :

                    Tension the string \[=m\,(g+a)=\]Breaking force             Þ \[20(g+a)=25\times g\] Þ \[a=g/4=2.5\ m/{{s}^{2}}\]


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