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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of \[5\,m/{{s}^{2}},\] the reading of the spring balance will be                                 [AIEEE 2003]

    A)             49 N   

    B)             24 N

    C)             74 N   

    D)             15 N

    Correct Answer: B

    Solution :

                    When the lift is stationary \[W=mg\]             Þ \[49=m\times 9.8\] Þ \[m=5\,kg.\]             When the lift is moving downward with an acceleration \[R=m\,(9.8-a)=5[9.8-5]=24N\]


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