JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    In the above problem, if the lift moves up with a constant velocity of 2 m/sec, the reading on the balance will be [NCERT 1977]            

    A)                         2 kg                 

    B)                         4 kg            

    C)                         Zero                

    D)                         1 kg

    Correct Answer: A

    Solution :

                                The lift is not accelerated, hence the reading of the balance will be equal to the true weight.                         \[R=mg=2g\ Newton\] or  2 kg            


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