question_answer

Mass of a person sitting in a lift is 50 kg. If lift is coming down with a constant acceleration of 10 \[m/se{{c}^{2}}.\] Then the reading of spring balance will be \[(g=10m/se{{c}^{2}})\]                    [RPET 2003; Kerala PMT 2005]

A)             0                     

B)             1000N

C)                         100 N           

D)                         10 N