A) 20 m
B) 40 m
C) 60 m
D) 80 m
Correct Answer: D
Solution :
The stopping distance, \[S\propto {{u}^{2}}\] \[(\because \ {{v}^{2}}={{u}^{2}}-2as)\] Þ \[\frac{{{S}_{2}}}{{{S}_{1}}}={{\left( \frac{{{u}_{2}}}{{{u}_{1}}} \right)}^{2}}={{\left( \frac{120}{60} \right)}^{2}}=4\] Þ \[{{S}_{2}}=4\times {{S}_{1}}=4\times 20=80\,m\]
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