JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is T. If the resultant acceleration becomes \[g/4,\] then the new time period of the pendulum is             [DCE 2004]

    A)             0.8 T   

    B)             0.25 T

    C)             2 T      

    D)             4 T

    Correct Answer: C

    Solution :

                    When lift is at rest, \[T=2\pi \sqrt{l/g}\] If acceleration becomes g/4 then \[{T}'=2\pi \sqrt{\frac{l}{g/4}}=2\pi \sqrt{\frac{4l}{g}}=2\times T\]


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