JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    N bullets each of mass m kg are fired with a velocity \[v\,m{{s}^{-1}}\] at the rate of n bullets per second upon a wall. The reaction offered by the wall to the bullets is given by

    A)                         nmv              

    B)                         \[\frac{Nmv}{n}\]            

    C)                         \[n\frac{Nm}{v}\]                  

    D)                         \[n\frac{Nv}{m}\]

    Correct Answer: A

    Solution :

                                Total mass of bullets = Nm, time \[t=\frac{N}{n}\] Momentum of the bullets striking the wall = Nmv             Rate of change of momentum (Force) = \[\frac{Nmv}{t}\]= nmv.            


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