JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    With what minimum acceleration can a fireman slides down a rope while breaking strength of the rope is \[\frac{2}{3}\] of his weight                            [CPMT 1979]

    A)                         \[\frac{2}{3}g\]                    

    B)                         g            

    C)                         \[\frac{1}{3}g\]                    

    D)                         Zero

    Correct Answer: C

    Solution :

                                If man slides down with some acceleration then its apparent weight decreases. For critical condition rope can bear only 2/3 of his weight. If a is the minimum acceleration then, Tension in the rope \[=m(g-a)\]= Breaking strength             Þ \[m(g-a)=\frac{2}{3}mg\] Þ\[a=g-\frac{2g}{3}=\frac{g}{3}\]              


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