A) 150 W
B) 550 W
C) 250 W
D) 50 W
Correct Answer: B
Solution :
[b] We know that, \[Z=\frac{{{E}_{0}}}{{{I}_{0}}}\] Given, \[{{E}_{0}}=220\] and \[{{I}_{0}}=10\] So \[Z=\frac{220}{10}=22\,ohm\] \[\phi =\left[ \frac{\pi }{6}-\left( -\frac{\pi }{6} \right) \right]=\frac{\pi }{3}\] \[{{P}_{a}}=\frac{{{E}_{0}}}{\sqrt{2}}\times \frac{{{I}_{0}}}{\sqrt{2}}\times \cos \]\[\phi =\frac{220}{\sqrt{2}}\times \frac{10}{\sqrt{2}}\times \cos \,\frac{\pi }{3}\]You need to login to perform this action.
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