A) 500 watt
B) 1014 watt
C) 1514 watt
D) 2013 watt
Correct Answer: C
Solution :
[c] \[{{i}_{1\,rms}}=\frac{{{E}_{rms}}}{\sqrt{X_{C}^{2}+R_{1}^{2}}}=\frac{130}{13}=10A\] \[{{i}_{2\,rms}}=\frac{{{E}_{rms}}}{\sqrt{X_{L}^{2}+R_{2}^{2}}}=13\,A\] Power dissipated \[={{i}^{2}}_{1\,rms}\,{{R}_{1}}+{{i}^{2}}_{2\,rms}{{R}_{2}}={{10}^{2}}\times 5+{{13}^{2}}+6\] = power delivered by battery \[=500+169\times 6=1514\,watt\]You need to login to perform this action.
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