A) \[\frac{L}{R}\]
B) \[\frac{2L}{R}\]
C) \[\frac{L}{2R}\]
D) None of these
Correct Answer: C
Solution :
[c] A circuit equivalent to the given circuit can be drawn as follows: Where \[{{R}_{eq}}=R+\frac{2R\times 2R}{4R}\] \[=R+R\] \[{{R}_{eq}}=2R\] \[\therefore \] Time constant \[=\frac{L}{2R}\]You need to login to perform this action.
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