1. \[f(x)=\] ln x is an increasing function on \[\left( 0,\infty \right).\] |
2. \[f(x)={{e}^{x}}-x(ln\,\,x)\] is an increasing function on \[\left( 1,\,\infty \right)\]. |
Which of the above statements is/are correct? |
A) 1 only
B) 2 only
C) Both 1 and 2
D) Neither 1 nor 2
Correct Answer: C
Solution :
[c] \[f(x)=\log \,x\] Clearly \[f(x)\] is increasing on \[(0,\infty )\] \[f(x)={{e}^{x}}-x\log x\] \[f'(x)={{e}^{x}}-(\log \,x+1)\] From the figure it is clear that \[f'(x)>0\] on \[(1,\infty )\]. So both statements (1) & (2) are correct.You need to login to perform this action.
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