A) \[\frac{1}{3}\] square unit
B) \[\frac{2}{3}\] square unit
C) \[\frac{4}{3}\] square units
D) 2 square units
Correct Answer: C
Solution :
[c] Area of \[ABCD=2\times 1=2\] sq. units Area of \[BAODC=\int_{-1}^{1}{{{x}^{2}}}dx=\left. \frac{{{x}^{3}}}{3} \right|_{-1}^{1}=\frac{2}{3}\] sq. units Required area \[=2-\frac{2}{3}=\frac{4}{3}\] sq. unitsYou need to login to perform this action.
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