A) 2 square unit
B) 4 square unit
C) 8 square unit
D) 16 square unit
Correct Answer: C
Solution :
[c] Required Area = \[2\int\limits_{y=0}^{4}{\frac{y}{2}dy=\left. \frac{{{y}^{2}}}{2} \right|_{0}^{4}=\frac{16}{2}=8}\] sq. unit. or Area \[=2\times 4=8\] sq. unit.You need to login to perform this action.
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