A) 1 square unit
B) 2 square units
C) 4 square units
D) 8 square units
Correct Answer: B
Solution :
[b] Required area \[=\int\limits_{0}^{2\pi }{\sin \,\,x\,\,dx}\] \[=-\cos \left. x \right|_{0}^{2\pi }=-\cos 2\pi -(-\cos 0)\] \[=-\cos (\pi +\pi )+1=-\,\,[-\cos \pi ]+1\] \[=+\cos \left( \frac{\pi }{2}+\frac{\pi }{2} \right)+1\] \[=\sin \frac{\pi }{2}+1=1+1=2\] sq. units.
You need to login to perform this action.
You will be redirected in
3 sec
