A) \[\frac{12}{7}\]
B) \[\frac{4}{3}\]
C) \[\frac{3}{4}\]
D) \[\frac{8}{3}\]
Correct Answer: B
Solution :
[b] Given curves are \[y={{x}^{2}}+3\] and \[y=2x+3\] points of intersection are (0, 3) and (2, 7) \[\therefore \] Required area \[=\left| \int\limits_{0}^{2}{({{x}^{2}}-2x)dx} \right|=\left| \frac{{{x}^{3}}}{3}-\frac{2{{x}^{2}}}{2} \right|_{0}^{2}\] \[=\left| \frac{8}{3}-4 \right|=\frac{4}{3}\] sq. unit
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