question_answer

The area enclosed by the curve \[{{x}^{2}}y=36,\] the x-axis and the lines x = 6 and x = 9 is

A) 6

B) 1

C) 4

D) 2

Correct Answer: D

Solution :

[d] \[y=\frac{36}{{{x}^{2}}},x=6,x=9\] Desired area \[=\int\limits_{6}^{9}{\frac{36}{{{x}^{2}}}dx}\] \[=-36\left[ \frac{1}{9}-\frac{1}{6} \right]=2\]