A) \[{{2}^{10}}\]
B) \[{{3}^{10}}\]
C) 1
D) \[{{6}^{10}}\]
Correct Answer: D
Solution :
[d] Put \[x=y=z=1,\] the sum of coefficient \[={{(1+2+3)}^{10}}={{6}^{10}}\].
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