A) 1.6
B) 1.4
C) 1.8
D) 1.2
Correct Answer: A
Solution :
[a] \[{{(1.0002)}^{3000}}={{(1+0.0002)}^{3000}}\] \[=1+(3000)(0.0002)+\frac{(3000)(2999)}{1.2}{{(0.0002)}^{2}}+\] \[\frac{(3000)(2999)(2998)}{1.2.3}{{(0.0002)}^{3}}+....\] We want to get answer correct to only one decimal places and as such we have left further expansion. \[=1+(3000)(0.0002)=1.6\]
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