A) 1.1 times that of half-life
B) 2.2 times that of half-life
C) 3.3 times that of half-life
D) 4.4 times that of half-life
Correct Answer: C
Solution :
[c] \[{{t}_{90}}\]% \[=\frac{2.303}{k}\log \frac{100}{100-50}\,\,\,\,\,\,(I)\] \[{{t}_{50}}\]% \[=\frac{2.303}{k}\log \frac{100}{100-50}\,\,(II)\] \[\therefore {{t}_{90}}\]% \[=3.3\,{{t}_{50}}\]%You need to login to perform this action.
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