A) 2 hours
B) 1 hour
C) 0.5 hour
D) 0.25 hour
Correct Answer: B
Solution :
[b] \[A\to B\] For a first order reaction Given \[a=0.8\text{ }mol,\left( a-x \right)=0.8-0.6=0.2\] \[k=\frac{2.303}{1}log\frac{0.8}{0.2}or=2.303\,log4\] again \[a=0.9,a-x=0.9-0.675=0.225\] \[k=\frac{2.303}{t}\log \frac{0.9}{0.225}\] \[2.303log4=\frac{2.303}{t}log4\] Hence t=1 hourYou need to login to perform this action.
You will be redirected in
3 sec