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JEE Main & Advanced Mathematics Conic Sections Question Bank Self Evaluation Test - Conic Sections

  • question_answer
    Equation of the parabola whose vertex is \[(-3,-2),\] axis is horizontal and which passes through the point \[(1,2)\] is

    A) \[{{y}^{2}}+4y+4x-8=0\]

    B) \[{{y}^{2}}+4y-4x+8=0\]

    C) \[{{y}^{2}}+4y-4x-8=0\]

    D) None of these

    Correct Answer: C

    Solution :

    [c] Since the axis is horizontal an vertex is \[(-3,-2),\] \[\therefore \] The equation of the parabola must be of the form \[{{(y+2)}^{2}}=4a(x+3)\] It passes through \[(1,2),\] so \[16=16a\].i.e., a = 1. Hence, the equation of the required parabola is \[{{(y+2)}^{2}}=4(x+3)\] or \[{{y}^{2}}+4y-4x-8=0\]


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