A) \[0\]
B) \[1\]
C) \[-1\]
D) \[n\]
Correct Answer: D
Solution :
[d] We know, if A is an \[n\times n\] matrix, then \[\det (\lambda A)={{\lambda }^{s}}\det (A)\] But given \[\det (\lambda A)={{\lambda }^{s}}\det \,A\Rightarrow s=n\]
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