A) \[\alpha \]
B) \[\left( \frac{1}{\alpha } \right)I\]
C) \[I\]
D) \[\alpha I\]
Correct Answer: D
Solution :
[d] Since, adjoint of the square matrix A is B \[\Rightarrow \frac{B}{\left| A \right|}={{A}^{-1}}\] \[\Rightarrow \frac{AB}{\left| A \right|}=A{{A}^{-1}}=I\] \[\Rightarrow AB=\left| A \right|I\Rightarrow AB=\alpha I\]
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