A) \[{{x}^{2}}+{{y}^{2}}=13\]
B) \[{{y}^{2}}=\frac{9}{2}x\]
C) \[\frac{{{x}^{2}}}{8}+\frac{{{y}^{2}}}{18}=1\]
D) \[xy=c\]
Correct Answer: D
Solution :
[d] Differentiate \[xy(x)={{x}^{2}}y'(x)+2xy(x)\] or \[xy(x)+{{x}^{2}}y'(x)=0\] or \[x\frac{dy}{dx}+y=0\] or \[ln\,\,y+ln\,\,x=ln\,\,c\] or \[xy=c\]You need to login to perform this action.
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