A) 1, 1
B) 2, 1
C) 1, 2
D) 2, 2
Correct Answer: A
Solution :
[a] The eq. of parabolas having vertex at (0, 0) & focus at (a, 0), where (a > 0) is: \[{{y}^{2}}=4ax\] ? (i) \[2y.\frac{dy}{dx}=4a\] [On differentiating] On putting the value of (4a) in eq. (1) we get, \[2x.\frac{dy}{dx}-y=0\] in order =1 & degree = 1.You need to login to perform this action.
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