A) \[\cot \theta \]
B) \[\cos \theta \]
C) \[\tan \theta \]
D) \[\sin \theta \]
Correct Answer: C
Solution :
[c] \[T\sin \theta =\frac{\sigma }{{{\varepsilon }_{0}}K}.q\] ?.(i) \[T\cos \theta =mg\] ?(ii) Dividing (i) by (ii), \[\tan \theta =\frac{\sigma q}{{{\varepsilon }_{0}}K.mg}\text{ }\therefore \sigma \propto \tan \theta \]You need to login to perform this action.
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