A) \[\frac{{{N}_{A}}}{20}\]
B) \[\frac{{{N}_{A}}}{10}\]
C) \[\frac{{{N}_{A}}}{5}\]
D) \[\frac{{{N}_{A}}}{2}\]
Correct Answer: C
Solution :
[c] \[Cu\xrightarrow{{}}C{{u}^{++}}+2{{e}^{-}}\] i.e, to deposit 1 mole of Cu at cathode from \[C{{u}^{2+}}SO{{_{4}^{2-}}^{~}}\]solution = 2 moles of electrons are required i.e. To deposit \[6.35g=\frac{6.35}{63.5}\times 2=\frac{2}{10}=\frac{1}{5}moles\] Thus total no. of electrons required \[=\frac{{{N}_{A}}}{5}\]You need to login to perform this action.
You will be redirected in
3 sec