A) 123.0 g
B) 61.5 g
C) 10.2 g
D) 20.5 g
Correct Answer: A
Solution :
[a] \[ArN{{O}_{2}}+6{{H}^{+}}+6{{e}^{-}}\xrightarrow{{}}ArN{{H}_{2}}+2{{H}_{2}}O\] \[W=\frac{E.wt\times Q}{96500};20.50=\frac{M}{6}\times \frac{2\times 96500}{96500}\times \frac{50}{100}\] \[\therefore \text{ }M=123.0\text{ }g\]You need to login to perform this action.
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