A) 2 A
B) 3 A
C) 4 A
D) 5 A
Correct Answer: B
Solution :
[b] \[\phi \] (flux linked) \[={{a}^{2}}B\,\cos \,{{0}^{o}}-{{b}^{2}}B\,\cos \,{{180}^{o}}\] \[E=-\frac{d\phi }{dt}=-({{a}^{2}}-{{b}^{2}})\frac{dB}{dt}\] \[=({{a}^{2}}-{{b}^{2}}){{B}_{0}}\,\omega \cos \,\omega t\] where \[B={{B}_{0}}\], \[\sin \,\omega t\], \[{{B}_{0}}={{10}^{-3}}T\], \[\omega =100\] \[\therefore \,\,\,\,{{I}_{\max }}=({{a}^{2}}-{{b}^{2}})\frac{{{B}_{0}}\omega }{R}\] and \[R=(4a+4b)r=4(a+b)r\] \[\therefore \,\,\,\,{{I}_{\max }}=\frac{(a-b){{B}_{0}}\omega }{4r}=\frac{(1-0.4)\times {{10}^{-3}}\times 100}{4\times 5\times {{10}^{-3}}}=3A\]You need to login to perform this action.
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