A) Decrease by 1%
B) decrease by 2%
C) Increase by 1%
D) increase by 2%
Correct Answer: D
Solution :
[d] As \[g=\frac{GM}{{{R}^{2}}}\] when radius is reduced by 1% then \[R'=R-\frac{R}{100}=.99R,\] so \[\operatorname{g}'=\frac{GM}{{{(.99R)}^{2}}}=1.02\frac{GM}{{{R}^{2}}}\] \[\Rightarrow \text{ }%\text{ }increase\text{ }=2%\]You need to login to perform this action.
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