A)
B) \[C{{H}_{3}}CH\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,OONa\]
C) \[HOC{{H}_{2}}-CH=C{{H}_{2}}\]
D) \[C{{H}_{3}}\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,HOCl\]
Correct Answer: A
Solution :
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