A) \[N{{H}_{3}}\] and \[{{B}_{2}}{{H}_{6}}\]
B) \[NaH\] and \[Ca{{H}_{2}}\]
C) \[NaH\] and \[N{{\text{H}}_{3}}\]
D) \[Ca{{H}_{2}}\] and \[{{B}_{2}}{{H}_{6}}\]
Correct Answer: A
Solution :
[a] N and B belong to p-block and since the electronegativity difference between these elements and H is very less, they form covalent hydrides.
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