A) 30% of \[{{H}_{2}}{{O}_{2}}\] solution
B) \[30\text{ }c{{m}^{3}}\] solution contains 1g of \[{{H}_{2}}{{O}_{2}}\]
C) \[1\text{ }c{{m}^{3}}\] of solution liberates \[30\text{ }c{{m}^{3}}\] of \[{{O}_{2}}\] at STP
D) \[30\text{ }c{{m}^{3}}\] of solution contains 1 mole of \[{{H}_{2}}{{O}_{2}}\]
Correct Answer: C
Solution :
[c] 30 vol of \[{{H}_{2}}{{O}_{2}}\] means one volume of \[{{H}_{2}}{{O}_{2}}\]on decom-position will give 30 volume of oxygen.
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