| P: m divides n |
| Q: m divides \[{{n}^{2}}\] |
| R: m is prime, then |
A) \[Q\wedge R\to P\]
B) \[P\wedge Q\to R\]
C) \[Q\to R\]
D) \[Q\to P\]
Correct Answer: A
Solution :
[a] b.\[\frac{8}{4}=2,\frac{64}{4}=16;\] But 4 is not prime. Hence \[P\wedge Q\to R,\] false c. \[\frac{{{(6)}^{2}}}{12}=\frac{36}{12}=3;\] but 12 is not prime hence \[Q\to R,\] false d. \[\frac{{{(4)}^{2}}}{8}=\frac{16}{8}=2;\frac{4}{8}\] is not an integer hence\[Q\to P\]; false
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