A) \[\frac{{{u}^{2}}{{\cos }^{2}}\theta }{g}\]
B) \[\frac{{{u}^{2}}{{\cot }^{2}}\theta }{g\sin \theta }\]
C) \[\frac{{{u}^{2}}}{g}\]
D) \[\frac{{{u}^{2}}{{\tan }^{2}}\theta }{g\cos \theta }\]
Correct Answer: B
Solution :
[b] Horizontal components of velocity at O and P are equal. \[\therefore \text{v}\cos \left( 90{}^\circ -\theta \right)=\text{u}\cos \theta \] \[\text{or }\,\text{v sin}\theta =u\cos \theta \] \[\text{or }\,\text{v}\,\text{=}\,\,\text{u}\,\text{cos}\theta \] \[\text{At }\,\text{P, }\frac{\text{v}_{T}^{2}}{R}={{a}_{c}}\text{ ;}\] \[\frac{{{\text{u}}^{2}}{{\cot }^{2}}\theta }{g\sin \theta }=R\]You need to login to perform this action.
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