A) \[n=\frac{2hu}{g{{b}^{2}}}\]
B) \[n=\frac{2h{{u}^{2}}}{gb}\]
C) \[n=\frac{2h{{u}^{2}}}{g{{b}^{2}}}\]
D) \[n=\frac{h{{u}^{2}}}{g{{b}^{2}}}\]
Correct Answer: C
Solution :
[c] If the ball hits the nth step, then the horizontal distance traversed = nh. Here, the velocity along the horizontal direction = u. Initial velocity along the vertical direction = 0. |
So \[nb=ut\] ...(i) |
\[nh=0+\frac{1}{2}g{{t}^{2}}\] ...(ii). |
From \[t=\frac{nb}{v},\] putting in eq. (ii) |
\[nh=\frac{1}{2}g\times {{\left( \frac{nb}{u} \right)}^{2}}\] or \[n=\frac{2h{{u}^{2}}}{g{{b}^{2}}}\] |
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