A) 0.293g
B) 0.5g
C) 0.25g
D) 0.707g
Correct Answer: A
Solution :
[a] Use the relation \[N={{N}_{0}}{{e}^{-\lambda t}}\] where the decay constant \[\lambda =(0.693/{{T}_{half}}).\] The half-life period \[{{T}_{half}}\] is given to be 10min. The amount N of radioactive sample remaining at the end of 5 min comes out to be about \[0.707g,\] so that the amount of sample decayed is \[(1-0.707)=0.293g.\]You need to login to perform this action.
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