A) \[{{T}_{B}}/{{T}_{A}}\]
B) \[{{T}_{A}}/{{T}_{B}}\]
C) \[\frac{{{T}_{A}}+{{T}_{B}}}{{{T}_{A}}}\]
D) \[\frac{{{T}_{A}}-{{T}_{B}}}{{{T}_{A}}}\]
Correct Answer: A
Solution :
[a] \[{{T}_{1/2}}=\frac{In2}{\lambda }\,\,\therefore \,\,\lambda =\frac{In2}{{{T}_{1/2}}}\] \[\Rightarrow \,\,\,\,\,\,{{\lambda }_{A}}=\frac{In2}{{{T}_{A}}},\,\,\,\,{{\lambda }_{B}}=\frac{In2}{{{T}_{B}}}\Rightarrow \frac{{{\lambda }_{A}}}{{{\lambda }_{B}}}=\frac{{{T}_{B}}}{{{T}_{A}}}.\]You need to login to perform this action.
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