JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank Self Evaluation Test - Principle of Mathematical Induction

  • question_answer
    When \[{{2}^{301}}\] is divided by 5, the least positive remainder is

    A) 4

    B) 8

    C) 2

    D) 6

    Correct Answer: C

    Solution :

    [c]   \[{{2}^{4}}\equiv 1(mod5)\Rightarrow {{({{2}^{4}})}^{75}}\equiv {{(1)}^{75}}(mod5)\] i.e., \[{{2}^{300}}\equiv 1(mod5)\Rightarrow {{2}^{300}}\times 2\equiv (1.2)(mod5)\] \[\Rightarrow {{2}^{301}}\equiv 2(mod5)\] \[\therefore \] Least positive remainder is 2.


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